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一元一次方程的计算题,带答案

一元一次方程的计算题,带答案

7(2x-1)-3(4x-1)=4(3x+2)-1;(5y+1)+ (1-y)= (9y+1)+(1-3y);20%+(1-20%)(320-x)=320×40%2(x-2)+2=x+12(x-2)-3(4x-1)=9(1-x)x/3 -5 = (5-x)/22(x+1) /3=5(x+1) /6 -1(1/侍孙含5)x +1 =(2x+1)/4(5-2)/2 - (4+x)/3 =1x/3 -1 = (1-x)/2(x-2)/2 - (3x-2)/4 =-111x+64-2x=100-9x15-(8-5x)=7x+(4-3x)3(x-7)-2[9-4(2-x)]=223/2[2/3(1/老笑4x-1)-2]-x=22(x-2)-3(4x-1)=9(1-x)11x+64-2x=100-9x15-(8-5x)=7x+(4-3x)3(x-7)-2[9-4(2-x)]=223/2[2/3(1/4x-1)-2]-x=22(x-2)+2=x+11.7(2x-1)-3(4x-1)=4(3x+2)-12.(5y+1)+ (1-y)= (9y+1)+(1-3y)3.[ (- 2)-4 ]=x+24.20%+(1-20%)(320-x)=320×40%5.2(x-2)+2=x+16.2(x-2)-3(4x-1)=9(1-x)7.11x+64-2x=100-9x8.15-(8-5x)=7x+(4-3x)9.3(x-7)-2[9-4(2-x)]=2210.3/2[2/3(1/4x-1)-2]-x=211.5x+1-2x=3x-212.3y-4=2y+113.87X*13=514.7Z/93=4115.15X+863-65X=5416.58Y*55=2748917.2(x+2)+4=918.2(x+4)=1019.3(x-5)=1820.4x+8=2(x-1)21.3(x+3)=9+x22.6(x/2+1)=1223.9(x+6)=6324.2+x=2(x-1/2)25.8x+3(1-x)=-226.7+x-2(x-1)=127.x/3 -5 = (5-x)/228.2(x+1) /3=5(x+1) /6 -129.(1/5)x +1 =(2x+1)/凯搏4